\begin{questions}                                                                                              
     \Question[3] Evaluate \(2m(m-3n)\) when:                                                                   
         \begin{multicols}{3}                                                                                   
         \begin{parts}                                                                                          
             \part \(m=3,n=5\)                                                                                  
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(2 \cdot 3(3-3 \cdot 5) = 6(3-15) = 6(-12) = -72\)                                            
             \end{solutionordottedlines}                                                                        
             \part \(m=-3, n=-2\)                                                                               
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(2 \cdot (-3)(-3-3 \cdot (-2)) = -6(-3+6) = -6 \cdot 3 = -18\)                                
             \end{solutionordottedlines}                                                                        
             \part \(m=\frac{1}{3}, n=\frac{1}{2}\)                                                             
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(2 \cdot \frac{1}{3}\left(\frac{1}{3}-3 \cdot \frac{1}{2}\right) =                            
 \frac{2}{3}\left(\frac{1}{3}-\frac{3}{2}\right) = \frac{2}{3}\left(\frac{2-9}{6}\right) = \frac{2}{3} \cdot    
 \frac{-7}{6} = -\frac{7}{9}\)                                                                                  
             \end{solutionordottedlines}                                                                        
         \end{parts}                                                                                            
         \end{multicols}                                                                                        
     \Question[1] Evaluate \(\frac{p+2q}{3r}\) when \(p = 7, q = -2, r = 2\)                                    
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{7+2(-2)}{3 \cdot 2} = \frac{7-4}{6} = \frac{3}{6} = \frac{1}{2}\)                      
             \end{solutionordottedlines}                                                                        
     \Question[1] Evaluate \(\frac{x+y}{3}\) when \(x = -6, y = -5\)                                            
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{-6-5}{3} = \frac{-11}{3}\)                                                             
             \end{solutionordottedlines}                                                                        
     \Question[3] Fill in the missing term:                                                                     
         \begin{multicols}{3}                                                                                   
         \begin{parts}                                                                                          
             \part \(2a+\dotfill=7a\)                                                                           
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(2a+5a=7a\)                                                                                   
             \end{solutionordottedlines}                                                                        
             \part \(5m^2-\dotfill = -6m^2n\)                                                                   
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(5m^2-11m^2n = -6m^2n\)                                                                       
             \end{solutionordottedlines}                                                                        
             \part \(-6lm+\dotfill=lm\)                                                                         
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-6lm+7lm=lm\)                                                                                
             \end{solutionordottedlines}                                                                        
         \end{parts}                                                                                            
         \end{multicols}                                                                                        
     \Question[6] Simplify by collecting like terms:                                                            
         \begin{multicols}{3}                                                                                   
         \begin{parts}                                                                                          
             \part \(9a^2+5a^2-12a^2\)                                                                          
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(9a^2+5a^2-12a^2 = 2a^2\)                                                                     
             \end{solutionordottedlines}                                                                        
             \part \(14a^2d-10a^2d-6a^2d\)                                                                      
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(14a^2d-10a^2d-6a^2d = -2a^2d\)                                                               
             \end{solutionordottedlines}                                                                        
             \part \(17m^2-14m^2+8m^2\)                                                                         
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(17m^2-14m^2+8m^2 = 11m^2\)                                                                   
             \end{solutionordottedlines}                                                                        
             \part \(-4x^2+3x^2-3y-7y\)                                                                         
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-4x^2+3x^2-3y-7y = -x^2-10y\)                                                                
             \end{solutionordottedlines}                                                                        
             \part \(7x^3+6x^2-4y^3-x^2\)                                                                       
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(7x^3+6x^2-4y^3-x^2 = 7x^3+5x^2-4y^3\)                                                        
             \end{solutionordottedlines}                                                                        
             \part \(-3ab^2+4a^2b-5ab^2+a^2b\)                                                                  
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-3ab^2+4a^2b-5ab^2+a^2b = -8ab^2+5a^2b\)                                                     
             \end{solutionordottedlines}                                                                        
         \end{parts}                                                                                            
         \end{multicols}                                                                                        
     \Question[12] Simplify                                                                                     
         \begin{multicols}{4}                                                                                   
         \begin{parts}                                                                                          
             \part \(4a\times 3b\)                                                                              
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(4a \times 3b = 12ab\)                                                                        
             \end{solutionordottedlines}                                                                        
             \part \(-2p \times(-3q)\)                                                                          
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-2p \times(-3q) = 6pq\)                                                                      
             \end{solutionordottedlines}                                                                        
             \part \(27y \div 3\)                                                                               
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(27y \div 3 = 9y\)                                                                            
             \end{solutionordottedlines}                                                                        
             \part \(3 \times 12t \div 9\)                                                                      
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(3 \times 12t \div 9 = 4t\)                                                                   
             \end{solutionordottedlines}                                                                        
             \part \(24x\div 8 \times 3\)                                                                       
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(24x\div 8 \times 3 = 9x\)                                                                    
             \end{solutionordottedlines}                                                                        
             \part \(-\frac{12m}{18}\)                                                                          
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-\frac{12m}{18} = -\frac{2}{3}m\)                                                            
             \end{solutionordottedlines}                                                                        
             \part \(\frac{12ab}{4a}\)                                                                          
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{12ab}{4a} = 3b\)                                                                       
             \end{solutionordottedlines}                                                                        
             \part \(\frac{3x}{5}\times\frac{2}{3}\)                                                            
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{3x}{5}\times\frac{2}{3} = \frac{2x}{5}\)                                               
             \end{solutionordottedlines}                                                                        
             \part \(\frac{2}{5a}\times\frac{1}{4a}\)                                                           
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{2}{5a}\times\frac{1}{4a} = \frac{2}{20a^2} = \frac{1}{10a^2}\)                         
             \end{solutionordottedlines}                                                                        
             \part \(\frac{3x}{5}\div\frac{3}{4}\)                                                              
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{3x}{5}\div\frac{3}{4} = \frac{3x}{5} \times \frac{4}{3} = \frac{4x}{5}\)               
             \end{solutionordottedlines}                                                                        
             \part \(\frac{9y}{2}\div 18\)                                                                      
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{9y}{2}\div 18 = \frac{9y}{2} \times \frac{1}{18} = \frac{y}{4}\)                       
             \end{solutionordottedlines}                                                                        
             \part \(\frac{5p}{6}\div(-\frac{10p}{3})\)                                                         
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{5p}{6}\div(-\frac{10p}{3}) = \frac{5p}{6} \times \frac{-3}{10p} = -\frac{1}{4}\)       
             \end{solutionordottedlines}                                                                        
         \end{parts}                                                                                            
         \end{multicols}                                                                                        
     \Question[4] Fill in the missing boxes. Each box contains the product of the 2 boxes below it.             
         \begin{multicols}{2}                                                                                   
         \begin{centering}                                                                                      
         \begin{parts}                                                                                          
             \part                                                                                              
                 \begin{centering}                                                                              
                 \begin{tikzpicture}                                                                            
                     \draw (0,0) rectangle (1,1);                                                               
                     \draw (1,0) rectangle (2,1);                                                               
                     \draw (2,0) rectangle (3,1);                                                               
                     \draw (0.5,1) rectangle (1.5,2);                                                           
                     \draw (1.5,1) rectangle (2.5,2);                                                           
                     \draw (1,2) rectangle (2,3);                                                               
                                                                                                                
                     \node at (0.5,0.5) {$2a$};                                                                 
                     \node at (1.5,0.5) {$4b$};                                                                 
                     \node at (2.5,0.5) {$5a$};                                                                 
                     \node at (1,1.5) {$8ab$};                                                                  
                     \node at (2,1.5) {$20ab$};                                                                 
                     \node at (1.5,2.5) {$160a^2b$};                                                            
                 \end{tikzpicture}                                                                              
                 \end{centering}                                                                                
             \part                                                                                              
                 \begin{centering}                                                                              
                 \begin{tikzpicture}                                                                            
                     \draw (0,0) rectangle (1,1);                                                               
                     \draw (1,0) rectangle (2,1);                                                               
                     \draw (2,0) rectangle (3,1);                                                               
                     \draw (0.5,1) rectangle (1.5,2);                                                           
                     \draw (1.5,1) rectangle (2.5,2);                                                           
                     \draw (1,2) rectangle (2,3);                                                               
                                                                                                                
                     \node at (1,1.5) {$24a$};                                                                  
                     \node at (1.5,2.5) {$48a^2b$};                                                             
                     \node at (2.5,0.5) {$2b$};                                                                 
                     \node at (0.5,0.5) {$12a$};                                                                
                     \node at (1.5,0.5) {$2a$};                                                                 
                     \node at (2,1.5) {$4ab$};                                                                  
                 \end{tikzpicture}                                                                              
                 \end{centering}                                                                                
         \end{parts}                                                                                            
         \end{centering}                                                                                        
         \end{multicols}                                                                                        
     \Question[8] Expand:                                                                                       
         \begin{multicols}{4}                                                                                   
         \begin{parts}                                                                                          
             \part \(b(b+7)\)                                                                                   
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(b(b+7) = b^2+7b\)                                                                            
             \end{solutionordottedlines}                                                                        
             \part \(4h(5h-7)\)                                                                                 
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(4h(5h-7) = 20h^2-28h\)                                                                       
             \end{solutionordottedlines}                                                                        
             \part \(-k(5k-4)\)                                                                                 
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-k(5k-4) = -5k^2+4k\)                                                                        
             \end{solutionordottedlines}                                                                        
             \part \(-4x(3x-5)\)                                                                                
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-4x(3x-5) = -12x^2+20x\)                                                                     
             \end{solutionordottedlines}                                                                        
             \part \(4c(2c-d)\)                                                                                 
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(4c(2c-d) = 8c^2-4cd\)                                                                        
             \end{solutionordottedlines}                                                                        
             \part \(-3x(2x+5y)\)                                                                               
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-3x(2x+5y) = -6x^2-15xy\)                                                                    
             \end{solutionordottedlines}                                                                        
             \part \(3p(2-5pq)\)                                                                                
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(3p(2-5pq) = 6p-15p^2q\)                                                                      
             \end{solutionordottedlines}                                                                        
             \part \(-10b(3a-7b)\)                                                                              
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-10b(3a-7b) = -30ab+70b^2\)                                                                  
             \end{solutionordottedlines}                                                                        
         \end{parts}                                                                                            
         \end{multicols}                                                                                        
     \Question[6] Expand and collect like terms                                                                 
         \begin{multicols}{3}                                                                                   
         \begin{parts}                                                                                          
             \part \(\frac{1}{4}(x+2)+\frac{x}{3}\)                                                             
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{1}{4}(x+2)+\frac{x}{3} = \frac{1}{4}x+\frac{1}{2}+\frac{x}{3} =                        
 \frac{7}{12}x+\frac{1}{2}\)                                                                                    
             \end{solutionordottedlines}                                                                        
             \part \(\frac{3}{7}(3x+5)+\frac{x}{3}\)                                                            
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(\frac{3}{7}(3x+5)+\frac{x}{3} = \frac{9}{7}x+\frac{15}{7}+\frac{x}{3} =                      
 \frac{37}{21}x+\frac{15}{7}\)                                                                                  
             \end{solutionordottedlines}                                                                        
             \part \(-\frac{1}{2}(3x+2)-\frac{2x}{5}\)                                                          
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(-\frac{1}{2}(3x+2)-\frac{2x}{5} = -\frac{3}{2}x-1-\frac{2x}{5} = -\frac{19}{10}x-1\)         
             \end{solutionordottedlines}                                                                        
             \part \(2p(3p+1)-5(p+1)\)                                                                          
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(2p(3p+1)-5(p+1) = 6p^2+2p-5p-5 = 6p^2-3p-5\)                                                 
             \end{solutionordottedlines}                                                                        
             \part \(2p(3p+1)-4(2p+1)\)                                                                         
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(2p(3p+1)-4(2p+1) = 6p^2+2p-8p-4 = 6p^2-6p-4\)                                                
             \end{solutionordottedlines}                                                                        
             \part \(4z(4z-2)-z(z+2)\)                                                                          
             \begin{solutionordottedlines}[2cm]                                                                 
                 \(4z(4z-2)-z(z+2) = 16z^2-8z-z^2-2z = 15z^2-10z\)                                              
             \end{solutionordottedlines}                                                                        
         \end{parts}                                                                                            
         \end{multicols}                                                                                        
     \Question[8] Expand:                                                                                       
         \begin{multicols}{4}                                                                                   
         \begin{parts}                                                                                          
             \part \((x-6)(x-4)\)                                                                               
             \begin{solutionordottedlines}[2cm]                                                                 
                 \((x-6)(x-4) = x^2-4x-6x+24 = x^2-10x+24\)                                                     
             \end{solutionordottedlines}                                                                        
             \part \((4x+1)(3x-1)\)                                                                             
             \begin{solutionordottedlines}[2cm]                                                                 
                 \((4x+1)(3x-1) = 12x^2-4x+3x-1 = 12x^2-x-1\)                                                   
             \end{solutionordottedlines}                                                                        
             \part \((4x+3)(2x-1)\)                                                                             
             \begin{solutionordottedlines}[2cm]                                                                 
                 \((4x+3)(2x-1) = 8x^2-4x+6x-3 = 8x^2+2x-3\)                                                    
             \end{solutionordottedlines}                                                                        
             \part \((x-4)(2x+5)\)                                                                              
             \begin{solutionordottedlines}[2cm]                                                                 
                 \((x-4)(2x+5) = 2x^2+5x-8x-20 = 2x^2-3x-20\)                                                   
             \end{solutionordottedlines}                                                                        
             \part \((x+3)(x+3)\)                                                                               
             \begin{solutionordottedlines}[2cm]                                                                 
                 \((x+3)(x+3) = x^2+3x+3x+9 = x^2+6x+9\)                                                        
             \end{solutionordottedlines}                                                                        
             \part \((2x-5)(x+3)\)                                                                              
             \begin{solutionordottedlines}[2cm]                                                                 
                 \((2x-5)(x+3) = 2x^2+6x-5x-15 = 2x^2+x-15\)                                                    
             \end{solutionordottedlines}                                                                        
             \part \((